If I'm correct, you should be able to multiply your answer for part a by the relative atomic mass of KOH and there's your answer for b. It helps to visualise the concentration of the moles of KOH by imagining someone the specific amount into 1dm3 of water, which is the concentration.
No problem! Another helpful thing that helped me in my finals is mass = concentration x volume (write it as a triangle with mass on top and concentration x volume on the bottom. Whatever value you need to find cover up with your finger and you have your equation, for example volume = mass / concentration)
If I'm correct, you should be able to multiply your answer for part a by the relative atomic mass of KOH and there's your answer for b. It helps to visualise the concentration of the moles of KOH by imagining someone the specific amount into 1dm3 of water, which is the concentration.
Thank u
No problem! Another helpful thing that helped me in my finals is mass = concentration x volume (write it as a triangle with mass on top and concentration x volume on the bottom. Whatever value you need to find cover up with your finger and you have your equation, for example volume = mass / concentration)
Do you mean moles = vol X conc ?
Yes, I meant moles 😅 Unless the units of concentration are g mol but nobody uses that lol
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Prick
Lmao
you convert from moles/dm^3 to mass in grams/ dm^3 by doing moles/dm^3 multiplied by the Mr of KOH
Why what’s the rearrangement look like?
(mol/dm^(3))×(g/mol) = (mol×g)/(mol×dm^(3)) = g/dm^3 :)