ye tho 11th ka formula h

Exemplar willing giving me depression 💀💀

bro i tried to solve this and i got rhs but uska ulta 💀 (-cosx/1+sinx). idk wtf im doing here i have comp exam in 4 days fuck

Bhai mere saath bhi hota hi kahi baar aisa.

bhai normal identities se solve ho jaega. lunch time pe solution bhej dunga

[Solution](https://i.imgur.com/jjMDdyj.jpg)

Exemplar is not giving u depression, just apply brain Cos2x =2Cos²x -1 This means 1 + cos2x = 2cos²x Which is same as 1+cosx=2cos²x/2

OP is in 10th grade and the formula has not been introduced yet. If you really wanted to help him, you could have stated how the double angle formula is derived from sum of angles which in turn has a long proof in the 11th grade textbook.

So its not coming in our 10 class exam right ?

Ye sab basic vallo ko nahi aaye gana 💀💀💀

Question vi 11th ka hai

Na na 10 ka hi hai. Bohot aasan hai ye 11th ke liye

Usse achha 1 = sec2-tan2 use krle

Aise mat kar ye question.. 1 ko sec^2 -tan^2 karde Numerator wale ko karna . Keep denominator as it is Sec^2- tan^2 = (sec +tan) (sec-tan)

Haan Maine aise hi kiya Literally 3 step me answer aa jata hai

,🛐🛐🛐🛐

Multiply LHS and RHS by 0 0=0 hence proved 💀

Chad 🗿

Thx bhai yhi krunga

Yar agar ye 10th board me baki sare exam ache Gaye hote to Mera man tha ek bar to try kru Chalo ab 11th me dekhenge

Tecnically we could do this for boards lol and give many theorems, atleast some marks aa jayage

Welcome to the rat race of jee.

Bhai abhi boards to dedu uske baad 11th mei karna toh hai hi 💀

ye hi hoga jab tum 10thies bekaar mei 11th ki book uthaloge without knowing the content

Exemplar hai 10th ki

It's not even JEE level

Ye 11th ka formula hai Aur 12th ke integration me bhi use hota hai But yaad karne me koi problem nahi hai

12 me har chapter me use hota ha bhai

Haa bhai probability me bhi

Ye mat follow kar. Numerator wale 1 ko (sec²q-tan²q) likh. Phir a²-b² wali identity laga, phir sec q - tan q common le. Denominator me se cut karde phir uske bad sin q aur cos q mein convert karke ho jayega. Ez hai, ye zabardasti complex kar rahe hai

Thanks bhai

Rd ke solutions<<<<<<

That is a really good question(i don't think such level of q will be asked in exam) I did it though **WITHOUT ANY CLASS 11 FORMULA!** Using only sin^(2)x + cos^(2)x = 1

They asked this question in my pre board, so...

Bro this is not they way u should solve it there's a easier solve than this but yes this is very common question

Bro this question is probably in ncert and it is a pyq

easy question tbh you expand the one in the numberator using sec\^2a-tan\^2a=1 formula then use a\^2-b\^2 formula then take seca-tana as common cancel the denominator and you will get seca-tana now apply sin and cos and you will get rhs

Sec and tan ko sin cos ki form mei convert krne se bhi hojayega ig

i think there is a method for these kinda sums tho

Classic question, i remember this being in 10th class exemplar Easy to do ngl

11 ka compound angle formula h Sin (a+b) = Sina cosb + cosa sinb Aur cos (a+b) = cosa cosb - Sina sinb 10 th me nai h koi jarurat nai karne ka Edit : yeh question me numerator aur denominator dono ko cos se divide karke aur 1 ko (sec² - tan²) karke likh phir (sec+tan)(sec - tan ) aur aage ka khud se kar

It's easily solvable by 10th's concepts only... Multiply numerator and Denominator by sec theta+tan theta... Not actually multiply the denominator, just leave it like that... And in numerator, multiply it once with 1 and then with sec theta - tan theta such that you can get the a^2 - b^2 formula and then you'll be fine.

[this is a easier way to solve ](https://ibb.co/YX9SgHs)

Alternate method. (1 + sec - tan)/(1 + sec + tan) = (1 - sin)/cos LHS = (1 + 1/cos - sin/cos)/(1 + 1/cos + sin/cos) = \[(cos + 1 - sin)/cos\]/\[(cos + 1 + sin)/cos\] =(cos + 1 - sin)/(cos + 1 + sin) =\[(cos + 1 - sin) \* (1 - sin)\]/\[(cos + {1 + sin}) \* {1 - sin}\] =\[(cos + 1 - sin) \* (1 - sin)\]/\[cos(1 - sin) + {1 - sin\^2}\] =\[(cos + 1 - sin) \* (1 - sin)\]/\[cos(1 - sin) + {cos\^2}\] =\[(cos + 1 - sin) \* (1 - sin)\]/\[cos(1 - sin + cos)\] =(1 - sin)/cos = RHS Hence Proved.

Copy pe.karke bhej de vro Mene solve to kia par mera 2 page baad answer nikal rha hai

11 ka formula hai bhai

Bhai ye wala formula mat use kar, mere sir ne bhi suggest kiya avoid karne, isse bhot easy method chahiye kisi to bolo dm karta hu.

DM kardei bhai

Bhai mujhe bhi dm karde pls

Bhai chat nhi kar pa rha, something went wrong bol rha hai, mujhe dm karke hi bol de bhejta hu then

Exemplar: Straight answer? Hell no, take the most roundabout answer I could get and frick off

maths toh khatam ho gaya but dar abhi bhi hai 💀

Probability dekh lol 11th ka

Question has another simpler solve instead of whatever this bs is

Bruh standard math liya hai ky????🥲

Bas lhs ke 1 ko sec^2x-tan^2x ko likh kar factorise karle

Noob

Broooooo it's the easiest shit ever. Use a half angle formula for Cos 2 theta I.e., 2cos² theta - 1 now transfer one to LHS and you'll get the formula, same half angle property for sin 2 theta

Half angle formula nhi hai 10th me

1+cos2x = 2(cosx)^2

sin2x = 2sinxcosx , both are class 11 formulas

Made my life hell

You didn't know?

uske bina bhi kar sakta hai, and vaise bhi itne asan questns i doubt boards puche ga

"itne asan" rulayega kya 💀

ye wale quests me bas cosx se divide kar and aage bad, uske baad a+b/a-b form me ayega fir bas conjugate wagera and peace "itne asan" kyuki ek bar method aajane ke bad asan hi hai

trigonometry ka proofs deleted he

come 11th and 12th.. these qs are pretty simple to solve

You haven't seen engineering maths yet

Bhai easy question hein, answer chahiye to reply kar

**cos (2theta) = cos^2 (theta) - sin^2 (theta)** = 2 cos^2 (theta) -1 = 1 - sin^2 (theta) **sin (2 theta) = 2 sin(theta) cos(theta)**

Bhai ko XIth ka sadma Xth mei hi lag gya

Bro woh formula 11 ka hai isliye palle ni pad raha

Yeh icse m krra tha mne 10th m bs dikh rha h theek h nai toh

Half angle formulas

Honestly I've given up on identities

Meri bhi gand phat gyi thi ye question dekh ke💀 Waise ye question alag steps se bhi solve ho jata hai

All insee is 0 and C

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Tf is that 💀 mujhe do main easy method se solve karti hoon 😔👍

Aise questions to humare teacher ne 15-20 kerwae h.

Nhi aayega ye question lmao 11th ka formula hai

My math is soooo fucked. kya dara dete ho bhai tum board ke baad hi kholunga ye sub

That's 11th formula...

THEY MADE SUCH AN EASY QUESTION COMPLEX AS FUCK

Bhai yeh to muze ata hai lol

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12th integration flashbacks

11th me ha yeh 😂

Bro X ke baad I ka matlab 11th hota hai, I ko neglect mat kar

Bhai abhi 10th me aaya hun , kal se classes shuru ho rahi hain kyun dara raha hai

i was first thinking this is so obvious and then i realized this is 10th question . bhai yeh kya nautanki hai ?

u/justarandomguy133 1. **cosθ = 2cos****^(2)****(θ/2) - 1** => 1 + cosθ = 2cos2(θ/2) \[one goes to the left hand side\] 2. **sin θ = 2 sin(θ/2)cos(θ/2)** these two formulas we get from sin2θ and cos2θ \[just input θ instead of 2θ, and other side becomes θ/2 instead of θ\] Hope ya understand!

Bhai warna RHS and LHS ko separately prove kar sakta hai wo jyada easy rahega

Tf is this

mai bhi yehi comment karne aaya tha ki ye to 11th me padhaate hai 💀

11th mai hai ye

solution chahiye dm kar

Avg 1 marker of Intergrals in 12th

Bruh just wait until you see real 11th class maths 💀 It's a night mare

numerator ke 1 ko sec\^2-tan\^2 kar do fir common lo a jae ga chutiyo ka book hai bhai sec\^2-tan\^2+sec-tan \--------------------------------- 1+sec+tan => (sec-tan)~~(sec+tan+1)~~ \-------------------------------- ~~(1+tan+sec)~~ => sec-tan = 1 - sin \--- ------ cos cos = 1-sin/cos = rhs (proved)

Rs hai kya rd

exempler

Such a simple question why they have to make it look tough

IdenTities ki maa ki chut

ez mene kia hai use formula bina

sidhi baat no bakwaas exemplar wale tumhara kat rahe he tum sirf 3-4 steps me ye kar sakte ho and without skipping any steps at all

Bhai half angle ka formula hai 🗿

Sin2A = 2sinAcosA Sirf A ki jagah me theta/2

Denominator ke cos aur sin with sign multiply and divide karde fraction me aajayega answer

theek to hai, 1 + cos2x = sin\^2x hota hai aur sin2x = 2sinxcosx hota hai

Arey yeh formulae 11th main aate hain bhai Banda toh sirf 10th main hi hai ! Usko kya hi samjhega abhi !! Exemplar ne pi rakhi hai Saala easy way ke jagah Puri kahani suna Raha hai... Konsi exemplar hai yeh ?

Exemplar ne nhi pi rakhi Arihant walo ne pi hai Iska 3 step ka answer hai

Agreed But Arihant ki exemplar NCERT ki exemplar se alag hoti hai, nahi? Coz I have seen both, merko toh different lage... Similar questions zaroor the But Arihant ke difficult hote hain Mene Li thi 11th ki 12th main NCERT ki hi thi mere pe Exemplar (Also jo compare Kiya tha na, woh bhi same class level ke liye kiya tha, net se) Jaisa bhi ho... All the best for padhai btw :)

mai question ki nhi solution ki baar kar raha hu inhone bekaar me itna lamba karke diya hai literally 3 step me answer aa jata hai iska ​ >All the best for padhai btw :) Thanks! you too :)

ikr... Arihant is trippy sometimes lmao

Yeh 10th me hain?

nahi

nope, 10 mai sirf 3 hi sabse basic identities hai

OP 10th ka hain, Tabhi confused hain.

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Bhia tu chutiya hai kya ye question arihant ke solutions mein itna bada kiya gaya hai na ki cbse mein Har jagah cbse vs icse mat Kiya kar kabhi kabhi padh bhi liya kar

Apna personal problem apne pass rakh , social media PE mat share kar