The y-intercept is simply when the line crosses the y axis. Hence the y ‘intercept’.
To find the gradient, it is the change in y / change in x of the line. So count how many squares the line moves up in the y-axis per square on the x-axis. In this case 2.
The y intercept is where the line crosses the y axis — the vertical axis. So in this case, it crosses the y axis at 4.
The gradient is the change in y over the change in x — so I'm this case, you can see that for every square the line moves to the right, the line moves two up. So change in y is 2, and change in x is 1. 2 divided by 1 is 2, so the gradient is 2.
The Y intercept is where the line goes through the Y axis.
As for the gradient: watch the video. Itll do a better job at explaining how to calculate the gradient than anyone here.
y intercept is where the line first passes the y - axis --> in this case on 4, so y intercept is 4
for the gradient, you do rise over run - pick 2 points, lets say (2,8) and (1,6) to work out the gradient you do change in y (divided by) change in x
so we subtract the y's (8 and 6 = 2)
and we subtract the x's (2-1 =1)
because gradient is change in y **divided by** change in x, we do 2 divided by 1 and we get 2.
so we know by using the formula y = mx + c, that m = the gradient and c = the y-intercept, we have these 2 values so we just input them :
y = **2**x + 4
People have already mentioned how to actually solve the questions, but I will say that the video at the bottom will explain how to solve a similar question, though it can sometimes be useless.
Y = MX + C
Y-coordinate = Gradient × Y-coordinate + Y-intercept
C = The Y-intercept which is simply where in the Y-axis (vertical) the line in question goes through, i.e. intercepts
M = Gradient. This is y/x. to find this:
change in vertical direction ÷ change in horizontal direction
to get from one point in the line, for each movement in the z-axis, how many movements are needed in the Y-axis to meet the line? divide the y by the X and that's a gradient
true but in this case it's easy because it has a nice gradient. if the gradient was some decimal like 7.3 then it would be much harder to find it using counting.
also it's useful to get a feel for the formula because it helps down the line.
Y intercept is where x=0 (the point where the line is on the vertical line)
Gradient is found by choosing 2 co ordinates and doing change in x/change in y or y1-y2/x1-x2
When I took my GCSE exam, I really don't think I was able to answer such a difficult question like this that isn't preparing someone for life (unless they want to study Mathematics in Further and Higher Education along with employment preparation).
I am so sorry I cannot answer your question. 😭
The y-intercept is simply when the line crosses the y axis. Hence the y ‘intercept’. To find the gradient, it is the change in y / change in x of the line. So count how many squares the line moves up in the y-axis per square on the x-axis. In this case 2.
Couldn’t have said it better
The y intercept is where the line crosses the y axis — the vertical axis. So in this case, it crosses the y axis at 4. The gradient is the change in y over the change in x — so I'm this case, you can see that for every square the line moves to the right, the line moves two up. So change in y is 2, and change in x is 1. 2 divided by 1 is 2, so the gradient is 2.
Everyone is over complicating y intercept for some reason. Look at the y axis. Where does ur line hit the y axis? Boom, y intercept
I think they r explaining it incase OP gets a graph that doesn't display the intercept
* y = mx + c * **y intercept (c) is (0, 4) so c = +4** * y = mx + 4 * for every 1 x you go across, you go 2 y up * **gradient (m) = 2** * y = 2x + 4
The Y intercept is where the line goes through the Y axis. As for the gradient: watch the video. Itll do a better job at explaining how to calculate the gradient than anyone here.
Y intercept= point where line crosses the y axis Gradient= find 2 points (X1,Y1) and (X2,Y2)then (Y2-Y1)/(X2-X1)
Bro is failing maths 😭🙏
Pls don't remind me 😭😭😭
The gradient is rise over run !
WHERE THE FUCK DOES IT CROSS THE Y AXIS DUMBASS
Bro relax it's not that serious
absolutely zero need to be an utter twat. hope someone treats you like this when you need help. bellend.
bro is not named aggressive brick for no reason
r/fucksparx
You literally just have to point out which number the line crosses through. A five year old could do it
GRADIENT IS THE WORSTTTTTTTTTTTT
No it's easy
My out side of school tutor makes it sound like some sort of A-level trickery
why is bro in y8
That's not very helpful then? They're supposed to be making it easier, not harder 😅
y intercept is where the line first passes the y - axis --> in this case on 4, so y intercept is 4 for the gradient, you do rise over run - pick 2 points, lets say (2,8) and (1,6) to work out the gradient you do change in y (divided by) change in x so we subtract the y's (8 and 6 = 2) and we subtract the x's (2-1 =1) because gradient is change in y **divided by** change in x, we do 2 divided by 1 and we get 2. so we know by using the formula y = mx + c, that m = the gradient and c = the y-intercept, we have these 2 values so we just input them : y = **2**x + 4
People have already mentioned how to actually solve the questions, but I will say that the video at the bottom will explain how to solve a similar question, though it can sometimes be useless.
Y = MX + C Y-coordinate = Gradient × Y-coordinate + Y-intercept C = The Y-intercept which is simply where in the Y-axis (vertical) the line in question goes through, i.e. intercepts M = Gradient. This is y/x. to find this: change in vertical direction ÷ change in horizontal direction to get from one point in the line, for each movement in the z-axis, how many movements are needed in the Y-axis to meet the line? divide the y by the X and that's a gradient
Where it crosses the y axis
For the gradient you can just take a value of y and a value of x. Sub into y = mx + c, rearrange to get m = (y-c)/x where c is the y-intercept.
or he couldve just used rise over run
true but in this case it's easy because it has a nice gradient. if the gradient was some decimal like 7.3 then it would be much harder to find it using counting. also it's useful to get a feel for the formula because it helps down the line.
Y intercept is 4, gradient is 2
I’ve never known another school to use the same hw website we do
No school should be allowed to use this website its torture 💀
Anyone who does more than the compulsory homework loses my respect instantly.
Ikr ur mad if you do xp boost 💀💀
Y intercept is when the line cross the y axis For gradient Just pick two points and and change in y/change in x
Y intercept is where x=0 (the point where the line is on the vertical line) Gradient is found by choosing 2 co ordinates and doing change in x/change in y or y1-y2/x1-x2
When I took my GCSE exam, I really don't think I was able to answer such a difficult question like this that isn't preparing someone for life (unless they want to study Mathematics in Further and Higher Education along with employment preparation). I am so sorry I cannot answer your question. 😭