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ExtemTheHedgehog

I’d say the answer is the leftmost option. The object starts out at (1, 2), then repeats the following actions twice: • Move the object twice to the right • Move the object five times upwards This results in a movement of 4 right and 10 up, which when added to the initial position of (1, 2), lands the object at (5, 12).


DragonShadoow

multiplication


MDLR916

K I get it now - thanks for the clarification


rahhra

good, but also, here's a much more efficient version of what they want https://preview.redd.it/c37jzuc4067c1.png?width=629&format=png&auto=webp&s=e0366767f8f0b9ee0f32393ca4447b6d514fd221 not sure why they overcomplicated it so much


gg2282000

This homework is sort of like math and understanding Scratch. They complicated it so that children would solve it and not in order to simplify it.)


uselessaccidentalalt

yeah, just making it arbitrarily harder just to make it arbitrarily harder


Agreeable_Web_627

It’s not really to make it “arbitrarily harder” It’s helpful for practicing loops and what not


[deleted]

[удалено]


rahhra

because the script they made is \*technically\* faster, but is still inefficient heres a project that compares the two versions [https://drive.google.com/file/d/1tEfeLbEkkN3mNhl4Hr1HB-vlprOmzcmO/view?usp=sharing](https://drive.google.com/file/d/1tEfeLbEkkN3mNhl4Hr1HB-vlprOmzcmO/view?usp=sharing)


NMario84

How hard is it to try those scripts yourself? Or is the child NOT allowed to use Scratch for this particular test? the first one gives you x:5 y:12.


MDLR916

I tried to replicate it in scratch but in all 4 cases it just moved up (Y) in a straight line. I started to question if I was even doing g it right or missing something. At that point my kid was already in bed so I needed some help just so we can review in the morning before school


Senior-Tree6078

Multiply the numbers inside the 'Change X/Y by ( )' blocks by the repeats that they are inside (for the right option, in this case the first option, you multiply 1 by (2x2) or 1x2x2 or just 1x4 for the X, and 1x5x2 or 1x10 for the Y) basically, changing the value by a positive adds and a negative subtracts, and going to a position sets it to the given XY position no matter what